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w = \frac{-1 \pm \sqrt{1 - 4}}{2} = \frac{-1 \pm \sqrt{-3}}{2} = \frac{-1 \pm i\sqrt{3}}{2}
So \(z^4 = \frac{-1 \pm i\sqrt{3}}{2} = e^{\pm 2\pi i/3}\), since these are the primitive cube roots of unity (excluding 1).
Thus, the solutions for \(z\) are the 4th roots of \(e^{2\pi i/3}\)

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